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x^2+14x-1.76=0
a = 1; b = 14; c = -1.76;
Δ = b2-4ac
Δ = 142-4·1·(-1.76)
Δ = 203.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-\sqrt{203.04}}{2*1}=\frac{-14-\sqrt{203.04}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+\sqrt{203.04}}{2*1}=\frac{-14+\sqrt{203.04}}{2} $
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